1.

In the figure, ABCDE is a pentagon with BE||CD and BC||DE. BC is perpendicular to CD. AB= 5cm, AE=5cm, BE= 7cm, BC= x-y and CD= x+y. If the perimeter of ABCDE is 27cm. find the value of x and y, given x, y ≠ 0.

Answer»

x + y = 7 and 2( x -y) + x +y +5 +5 = 27

∴ x + y = 7 and  3x -y = 27

Solving, we get, x = 6 and y = 1



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