1.

In the figure above, AB || CD. EF and FG are the bisectors of `angleBEG and angleDGE`, respectively. `angleFEG=angleFGE+10^(@)`. Find `angleFGE`.A. `20^(@)`B. `25^(@)`C. `40^(@)`D. `35^(@)`

Answer» Correct Answer - C
`AB||CD`
`angleBEG+angleEGD=180^(@)`
EF and FG bisect ` angleBEG and angleDGE,` respectively.
`:. 2 angleFEG+2 angleFGE=180^(@)`
`angleFEG+angleFGE=90^(@)" "`(1)
`angleFEG=angleFGE+10^(@)" "`(2)
On solving Eq. (1) and (2), we get `angleFGE=40^(@)`.
Hence, the correct option is ( c).


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