In the figure, an ideal liquid flows through the tube, which is of uniform cross section. The liquid has velocities `v_(A)` and `v_(B)`, and pressures `P_(A)` and `P_(B)` at the points `A` and `B`, respectively. Then A. `v_(B) gt v_(A)`B. `v_(B) =v_(A)`C. `P_(B) lt P_(A)`D. `P_(B)= P_(A)`

In the figure, an ideal liquid flows through the tube, which is of uni

1.	In the figure, an ideal liquid flows through the tube, which is of uniform cross section. The liquid has velocities `v_(A)` and `v_(B)`, and pressures `P_(A)` and `P_(B)` at the points `A` and `B`, respectively. Then A. `v_(B) gt v_(A)`B. `v_(B) =v_(A)`C. `P_(B) lt P_(A)`D. `P_(B)= P_(A)`
Answer» Correct Answer - B For a streamline flow of an ideal liquid, `v_(A)=v_(B)` . The pressure at B=Pressure at A+pressure dre to column of liquid of height AB.

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In the figure, an ideal liquid flows through the tube, which is of uniform cross section. The liquid has velocities `v_(A)` and `v_(B)`, and pressures `P_(A)` and `P_(B)` at the points `A` and `B`, respectively. Then A. `v_(B) gt v_(A)`B. `v_(B) =v_(A)`C. `P_(B) lt P_(A)`D. `P_(B)= P_(A)`

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