In the figure given alongside, find the values of x and y.

1.	In the figure given alongside, find the values of x and y.
Answer» In the given figure, side BC of ΔABC is produced to D. Consider the ΔABC, We know that the exterior angle of a triangle is equal to the sum of its interior opposite angles. ∴ ∠ABC + ∠BAC = ∠ACD = 68^o + x = 130^o = x = 130^o – 68^o = x = 62^o Also, we know that the sum of all the angles of a triangles is 180^o. ∴ x + y + 68^o = 180^o = 62^o + y + 68^o = 180^o = y + 130^o = 180^o = y = 180^o – 130^o = y = 50^o Hence, the value of x is 62^o and value of y is 50^o.

Answer»

In the given figure, side BC of ΔABC is produced to D.

Consider the ΔABC,

We know that the exterior angle of a triangle is equal to the sum of its interior opposite angles.

∴ ∠ABC + ∠BAC = ∠ACD

= 68^o + x = 130^o

= x = 130^o – 68^o

= x = 62^o

Also, we know that the sum of all the angles of a triangles is 180^o.

∴ x + y + 68^o = 180^o

= 62^o + y + 68^o = 180^o

= y + 130^o = 180^o

= y = 180^o – 130^o

= y = 50^o

Hence, the value of x is 62^o and value of y is 50^o.

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