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In the figure given below AABC, D is the midpoint of BC. DE ⊥ AB, DF ⊥ AC and DE = DF. Show that ΔBED ≅ AΔCFD. |
Answer» Given that D is the mid point of BC of ΔABC. DF ⊥ AC; DE = DF DE ⊥ AB In ΔBED and ΔCFD ∠BED = ∠CFD (given as 90°) BD = CD (∵D is mid point of BC) ED = FD (given) ∴ ΔBED ≅ ΔCFD (RHS congruence) |
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