1.

In the figure given below AC = AE; AB = AD and ∠BAD = ∠EAC. Show that BC = DE.

Answer»

Given that AC = AE, AB = AD and 

∠BAD = ∠EAC 

In ΔABC and ΔADE 

AB = AD 

AC = AE 

∠BAD = ∠EAC 

∴ ΔABC ≅ ΔADE (∵ SAS congruence) 

⇒ BC = DE (CPCT)



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