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In the figure given below AC = AE; AB = AD and ∠BAD = ∠EAC. Show that BC = DE. |
Answer» Given that AC = AE, AB = AD and ∠BAD = ∠EAC In ΔABC and ΔADE AB = AD AC = AE ∠BAD = ∠EAC ∴ ΔABC ≅ ΔADE (∵ SAS congruence) ⇒ BC = DE (CPCT) |
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