1.

In the figure given below, equilateral triangle EDC surmounts square ABCD. Find the angle DEB represented by x(1) 60° (2) 15° (3) 30° (4) 45°

Answer»

(4) 45°

EC = BC

∠BCE = 90 + 60 = 150°

∠CEB = ∠CBE = 15°

⇒ x = 45°



Discussion

No Comment Found

Related InterviewSolutions