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In the figure given below, equilateral triangle EDC surmounts square ABCD. Find the angle DEB represented by x(1) 60° (2) 15° (3) 30° (4) 45° |
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Answer» (4) 45° EC = BC ∠BCE = 90 + 60 = 150° ∠CEB = ∠CBE = 15° ⇒ x = 45° |
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