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In the figure, if m_(1) is at rest, find the relation among m_(1), m_(2) and m_(3) ? |
Answer» Solution :`m_(1)` is at rest `rArr` point B does not move, `m_(2)` and `m_(3)` move with ACCELERATION `a=((m_(3)-m_(2))/(m_(2)+m_(3)))G, m_(3)GT m_(2)` `T=(2m_(2)m_(3)g)/(m_(2)+m_(3)), T^(1)=2T=(4m_(2)m_(3)g)/(m_(2)+m_(3))` `m_(1)cancel(g)=(4m_(2)m_(3)cancel(g))/(m_(2)+m_(3)) "" [(4)/(m_(1))=(1)/(m_(2))+(1)/(m_(3))]` |
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