1.

In the figure light is incident on the thin lens as shown, the radius of curvature for both the surface is R. Determine the focal length of the system.

Answer»

Solution :For refraction at FIRST SURFACE,
`mu_2/v_1-mu_1/(-infty)= (mu_2-mu_1)/(+R)….(i)`
For refraction at `2^(nd)` surface
`mu_3/v_2=mu_2/v_1=(mu_3+mu_2)/(+R)`…….(ii)
Adding equations (i) and (ii) we get
`mu_3/v_2=(mu_3-mu_1)/R or v_2=(mu_3R)/(mu_3-mu_1)`
Therefore focal length of the GIVEN lens system is
`(mu_3R)/(mu_3-mu_1)`


Discussion

No Comment Found