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In the figure, PQ is a chord of a circle with centre O and PT is the tangent. If angle QPT = 60°, find angle PRQ. (Class 10) |
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Answer» Given, PQ is a chord of a circle with center O. Also, ∠QPT = 60°. Now, ∠QPT + ∠QPX = 180° [Linear pair] ⇒ ∠QPX = 180° - ∠QPT = 180° - 60° = 120° Again, ∠QPX = ∠PRQ [Alternate segment theorem] ⇒ ∠PRQ = 120° |
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