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In the figure, PT | QR and QT | RS. Show that arfAPQR)arQ1S) |
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Answer» Given that:PT || QR and QT || RSTo Prove:ar(ΔPQR)=ar(ΔQTS)Proof:Since triangle PQR and TQR are on the same base QR and between the parallels PT and QR. Therefore,ar(ΔPQR)=ar(ΔTQR).....(1)Similarly, triangle QTS and TQR are on the same base QT and between the parallels QT and RS. So,ar(ΔQTS)=ar(ΔTQR).....(2)From (1) and (2), we have,ar(ΔPQR)=ar(ΔQTS)Hence Proved. |
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