In the figure shown consider the first reflection at the plane mirror and second at the convex mirror .AB is object.

In the figure shown consider the first reflection at the plane mirror

1.	In the figure shown consider the first reflection at the plane mirror and second at the convex mirror .AB is object.
Answer» The second image is REAL ,inverted of `1//5^(th)`magnification the second image is virtual and erect with magnification `1//5` the second image moves towards the concave MIRROR. the second image moves away from the convex mirror. Solution : for image by convex mirror Distance of image of `A'`is `v_(A)` `(1)/(v)+(1)/(u)=(1)/(f)` `(1)/(v_(A))+(1)/(-60)=(1)/(60) rArr v_(A)=-30cm` Distance of image of `B'` is `v_(B)` `(1)/(v_(B)) +(1)/(-90)=(1)/(60)` `(1)/(v_(B)) =(1)/(60)+(1)/(90) rArr (1)/(v_(B))=(5)/(180)` `v_(B)=36cm` `m=("length of image")/("length of object")=(6)/(30)=(1)/(5)` Distance of image increases with convex mirror.