In the figure shown m_(1)=1kg, m_(2)=2kg, pulled is ideal. At t=0, both masses touches the ground and string is taut. A force F=2t is applied to pulley (t is in second) then (g=10m//s^(2))

In the figure shown m_(1)=1kg, m_(2)=2kg, pulled is ideal. At t=0, bot

1.	In the figure shown m_(1)=1kg, m_(2)=2kg, pulled is ideal. At t=0, both masses touches the ground and string is taut. A force F=2t is applied to pulley (t is in second) then (g=10m//s^(2))
Answer» `m_(2)` is lifted off the ground at t=20 sec `m_(1)` is lifted off the groudn at t=10 sec work done by TENSION in the STRING is `m_(1)` before `m_(2)` is lifted off the groudn is 1250 joule work done by tension in the string of `m_(1)` before `m_(2)` is lifted off the ground is zero Answer :A::B::C::D