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In the figure shown surfaces are smooth and blocks `A` and `B` have same mass `m`. The two bodies are displaced right and released. It is found that bodies move according to the equation `x_(A)=A sin(omegat+phi)`, `X_(B)=2Asin(omegat+phi)` A. `(K_(1))/(K_(2))=(3)/(2)`B. `(K_(1))/(K_(2))=(1)/(2)`C. `(K_(1))/(K_(2))=1`D. `(K_(1))/(K_(2))=2` |
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Answer» `K_(2)A=omega^(2)(2A)` `K_(1)A-K_(2)A=omega^(2)A` `rArr (K_(2))/(K_(1)-K_(2))=(2)/(1)` `rArr (K_(1))/(K_(2))=(3)/(2)` |
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