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In the figure shown the acceleration of A is, `vec(a)_(A) = 15 hat (i) + 15 hat (j)` then the acceleration of B is (A remains in contact in B) A. `6 hat(i)`B. `-15 hat(i)`C. `10 hat(i)`D. `-5 hat(i)` |
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Answer» Correct Answer - D Let acceleration of B `vec(a)_(B)=a_(B) hat(i)` Then acceleration of A w.r.t. `B=vec(a)_(A)-vec(a)_(R)=(15-a_(B))hat(i)+15 hat(j)` This acceleration must be along the inclined pplane so `tan 37^(@)=15/(15-a_(B))rArr 3/4=15/(15-a_(B)) a_(B)=-5` `rArr vec(a)_(R)=-5hat(i)` |
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