In the figure shown, the two identical balls of mass M and radius R each, are placed in contact with each other on the frictionless horizontal surface. The third ball of mass M and radius R//2, is coming down vertically and has a velocity = v_(0) when it simultaneously hits the two balls and itself comes to rest. Then, each of the two bigger balls will move after collision with a speed equal to

In the figure shown, the two identical balls of mass M and radius R ea

1.	In the figure shown, the two identical balls of mass M and radius R each, are placed in contact with each other on the frictionless horizontal surface. The third ball of mass M and radius R//2, is coming down vertically and has a velocity = v_(0) when it simultaneously hits the two balls and itself comes to rest. Then, each of the two bigger balls will move after collision with a speed equal to
Answer» `4v_(0)//SQRT(5)` `2v_(0)//sqrt(5)` `v_(0)//sqrt(5)` none of these Solution :`Jcostheta=Mv` ………..i ` -Jsintheta=0-Mv_(0)` `Jsintheta=Mv_(0)`………II from eqn i and ii `TANTHETA=v_(0)/v` ………..iii From `/_\AOC` `tantheta=(sqrt5R/2)/(R/2)=sqrt(5)` `sqrt(5)=v_(0)/vimpliesv=v_(0)/sqrt(5)`