1.

In the Figure, the blocks are of equal mass. The pulley is fixed & massless. In the position shown, A is given a speed u and vB= the speed of B. (θ < 90°)(A) B will never lose contact with the ground (B) The downward acceleration of A is equal in magnitude to the horizontal acceleration of B. (C) vB = ucosθ (D) vB = u/cosθ

Answer»

(A) B will never lose contact with the ground

(D) vB = u/cosθ



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