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In the figure two concentric conducting shells of radius R & 2R are shown. The inner shell is charged with Q and the shell is unchanged. The amount of energy dissipated when the shells are connected by a conducting wire is: A. `(KQ^(2))/(4R)`B. `(kQ^(2))/(2R)`C. `(kQ^(2))/(8R)`D. `(3kQ^(2))/4` |
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Answer» Correct Answer - A `U_(i)=(KQ^(2))/(2R) U_(t)=(KQ^(2))/(2(2R))` (whole charge will get transformed to outer sphere) so heat `=(KQ^(2))/(2(2R)) =(KQ^(2))/(4R)` |
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