1.

In the figure, two equal chords AB and CD of a circle with centre O, intersect each other at E, Prove that AD=CB

Answer» CF=CG
`/_CFE and /_CGE`
`angleCFE=angleCGE=90^o`
CE=CF
CF=CG
`/_CFEcong/_CGE`
so,FE=EG
Similarly,AF=DG
AF+FE=DG+GT
AE=DE
so,EB=EC
`/_AEC and /_DEB` is similar
`(AC)/(BD)=(AE)/(DE)=(CE)/(BE)=1`
So, AC=BD


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