In the figure X and Y are the mid points of AC and AB respectively, QP || BC and CYQ and BXP are straight lines. Prove that ar(△ABP)=ar(△ACQ).

In the figure X and Y are the mid points of AC and AB respectively, QP

1.	In the figure X and Y are the mid points of AC and AB respectively, QP \|\| BC and CYQ and BXP are straight lines. Prove that ar(△ABP)=ar(△ACQ).
Answer» In the figure X and Y are the mid points of AC and AB respectively, QP \|\| BC and CYQ and BXP are straight lines. Prove that $a r (△ A B P) = a r (△ A C Q) .$