1.

In the fluorite structure if the radius ratio is `(sqrt(3)/(2)-1)` how many ions does each cation touch?A. `4` anionsB. `12` cationsC. `8` anionsD. No cations

Answer» Correct Answer - B::C
`(r_(o+))/(r_(ɵ)) = sqrt(3/2) - 1 = 0.225`
Hence, it is the limiting case where cation in the void of fcc structure is not distorted.
So, number of cations surrounding the particular cation `= 12`. But at the same time `8` anions (present in `TVs`) touch the particul,ar cation.


Discussion

No Comment Found

Related InterviewSolutions