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In the following circuit, the resultant capacitance between `A` and `B` is `1muF`. Then value of `C` is A. `32/11muF`B. `11/32muF`C. `23/32muF`D. `32/23muF` |
Answer» Correct Answer - D From figure, equivalent capacitance of `6muF, 12muF and 4muF` condensers is, `C_(1)=8muF`. Similarly equivalent capacitance of `8muF, 2muF and 2muF` condensers is, `C_(2)=8//3muF`. The equivalent capacitance of `8muF and 1muF` condensers is, `C_(3)=8//9muF`. The equivalent of `C_(2) and C_(3)` is, `32//9muF`. Now, equivalent of C and `32//9muF` condenser is `1muF`. Thus, `C=32//23muF`. |
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