In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be A. `10 mV`B. `0.1V`C. `1.0V`D. `10V`

In the following common emitter configuration an `NPN` transistor with

1.	In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be A. `10 mV`B. `0.1V`C. `1.0V`D. `10V`
Answer» Correct Answer - C `"Voltage gain" ("Output voltage")/("Input voltage")` `implies V_(out)=V_("in")xx"Voltage gain"` `implies V_(out)=V_("in")xx"Current gain"xx"Resistance gain"` `=V_("in")xxbetaxx(R_(L))/(R_(BE))=10^(-3)xx100xx10/1=1V`.

Discussion

No Comment Found

Related InterviewSolutions

The depletion layer in diode is `1 mum` wide and the knee potential is `0.6 V`, then the electric field in the depletion layer will beA. zeroB. `0.6 Vm^(-1)`C. `6xx10^(4) V//m`D. `6xx10^(5)V//m`
The diagram shows an operational circuit. Which of the following correctely states the nature and magnitude of the amplification ? A. `{:("Nature","Magnitude of"(V_(0))/(V_(i))),("Inverting"," 0.2"):}`B. `{:("Nature","Magnitude of"(V_(0))/(V_(i))),("Inverting"," 5.0"):}`C. `{:("Nature","Magnitude of"(V_(0))/(V_(i))),("Non-inverting"," 0.2"):}`D. `{:("Nature","Magnitude of"(V_(0))/(V_(i))),("Non-inverting"," 5.0"):}`
The following truth table corresponds to the logic gate `|(A,0,0,1,1),(B,0,1,0,1),(X,0,1,1,1)|`A. `NAND`B. `OR`C. `AND`D. `XOR`
Which of the following gates corresponds to the truth table given below ? `|(A,B,X),(1,1,0),(1,0,1),(0,1,1),(0,0,1)|`A. `XOR`B. `OR`C. `NAND`D. `NOR`
The following truth table belongs to which one of the following four gates? `|(A,B,C),(1,1,0),(1,0,0),(0,1,0),(0,0,1)|`A. `OR`B. `NAND`C. `XOR`D. `NOR`
Pure sodium `(Na)` is a good conductor of electricity because the `3s` and `3p` atomic bands overlap to from a partially filled conduction band. By contrast the ionic sodium chloride `(NaCl)` crystal isA. InsulatorB. ConductorC. SemiconductorD. None of these
In an insulator, the forbidden energy gap between the valence band and conduction band is of the order ofA. `1 MeV`B. `0.1 MeV`C. `1 eV`D. `5 eV`
In a good conductor the energy gap between the conduction band and the valence band isA. InfiniteB. WideC. NarrowD. Zero
In a common emitter amplifier , when a signal of 40 mV is added to the input voltage, the base current changes by `100 muA` and emitter current changes by 2.1mA the trans-conductance isA. `1/20 Omega^(-1)`B. `1/50 Omega^(-1)`C. `50 Omega^(-1)`D. `15 Omega^(-1)`
In the given circuit, calculate the ratio of currents through the battery if (1) Key `K_(1)` is pressed, `K_(2)` open and then (2) Key `K_(2)` is pressed, key `K_(1)` is opened A. `1/2`B. 4C. 2D. 1

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be A. `10 mV`B. `0.1V`C. `1.0V`D. `10V`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment