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In the following dimensionally correct equation `F=(X)/("Linear Density")`, where F is the force. What is the dimensional formula for X?A. `M^(0)L^(0)T^(0)`B. `M L T^(-2)`C. `M^(2)L^(-2)T^(-2)`D. `M^(2)L^(0)T^(-2)` |
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Answer» Correct Answer - d By using the principle of homogeneity of dimensions, `|F|=|(X)/("Linear density")|" ... (1)"` But linear density = mass per unit length `therefore` [Linear density] `=[(M)/(L)]=[M^(1)L^(-1)]" ... from (1)"` `therefore [L^(1)M^(1)T^(-2)]=[(X)/(M^(1)L^(-1))]` `therefore [X]=[M^(2)L^(0)T^(-2)]` |
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