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In the following electrochemical cell `:` `Zn|Zn^(2+)||H^(o+)|(H_(2))Pt` `E_(cell)=E^(c-)._(cell).` This will be whenA. `[Zn^(2+)]=[H^(o+)]=1M` and `p_(H_(2))=1atm`B. `[Zn^(2+)]=0.01M,[H^(o+)]=0.1M,` and `p_(H_(2))=1atm`C. `[Zn^(2+)]=1M,[H^(o+)]=0.1M,` and `p_(H_(2))=1atm`D. None of the above. |
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Answer» Correct Answer - a,b Cell reaction `: Zn(s)+2H^(o+)(aq)rarr Zn^(2+) (aq)+H_(2)(g)` Using`:E_(cell)=E^(c-)._(cell)-(0.0591)/(2)log(Q_(cell)-(P_(H_(2))[Zn^(2+)])/([H^(o+)]^(2)))` `implies` For `E_(cell)=E^(c-)._(cell),Q_(cell)=1.0` `a. Q_(cell)=(1xx1)/(1^(2))=1` `b. Q_(cell)=(1xx0.01)/((0.1)^(2))=1` `c. Q_(cell)=(1xx1)/((0.1)^(2))=100` |
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