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In the following examples, given ∈ > 0, find a δ > 0 such that whenever, |x – a| < δ, we must have |f(x) – l| < ∈.\(\lim\limits_{x\longrightarrow2} (2x+3)=7 \)lim (2x +3) = 7 (x ∈ 2) |
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Answer» We have to find some δ so that \(\lim\limits_{x\longrightarrow2} (2x+3)=7 \) Here a = 2, l = 1 and f(x) = 2x + 3 Consider ∈ > 0 and |f(x) – l| < ∈ ∴ |(2x + 3) – 7| < ∈ ∴ |2x + 4| < ∈ ∴ 2(x – 2)|< ∈ ∴ |x – 2| < ∈/2 ∴ δ ≤ ∈/2 such that |2x + 4| < δ ⇒ |f(x) – 7| < ∈ |
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