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In the following figure a wire bent in the form of a regular polygon of `n` sides is inscribed in a circle of radius `a`. Net magnetic field at centre will be A. `B=(mu_(0)i)/(2pia)tan .(pi)/(n)`B. `B=(mu_(0)ni)/(2pia)tan .(pi)/(n)`C. `B=(2mu_(0)ni)/(pia)tan .(pi)/(n)`D. `B=(mu_(0)ni)/(2a)tan .(pi)/(n)` |
Answer» Correct Answer - 2 Magnetic field at the centre due to one side `B_(1)=(mu_(0)i)/(2pir)sin theta`, where `r=a cos theta` `:. B_(1)=(mu_(0)i)/(2piacos theta)sin theta=(mu_(0)i)/(2pia)tan theta , :. B_(n e t)=nB_(1)` |
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