In the following figure, ABCD is a parallelogram and BC is produced to a point Q such that AD = CQ. If AQ intersect DC at P, then show that area of(△BPC) = area of (△DPQ).

In the following figure, ABCD is a parallelogram and BC is produced to

1.	In the following figure, ABCD is a parallelogram and BC is produced to a point Q such that AD = CQ. If AQ intersect DC at P, then show that area of(△BPC) = area of (△DPQ).
Answer» In the following figure, ABCD is a parallelogram and BC is produced to a point Q such that AD = CQ. If AQ intersect DC at P, then show that area of( $△$ BPC) = area of ( $△$ DPQ).