In the following figure an isolated charged conductor is shown. The correct statement will be - A. `E_(A) gt E_(B) gt E_(C) gt E_(D)`B. `E_(A) lt E_(B) lt E_(C) lt E_(D)`C. `E_(A)=E_(B)=E_(C)=E_(D)`D. `E_(B)=E_(C)` and `E_(A) gt E_(D)`

In the following figure an isolated charged conductor is shown. The co

1.	In the following figure an isolated charged conductor is shown. The correct statement will be - A. `E_(A) gt E_(B) gt E_(C) gt E_(D)`B. `E_(A) lt E_(B) lt E_(C) lt E_(D)`C. `E_(A)=E_(B)=E_(C)=E_(D)`D. `E_(B)=E_(C)` and `E_(A) gt E_(D)`
Answer» Correct Answer - B Conductor is equipotential body, `V_(A)=V_(B)=V_(C)=V_(D)` For equipotential surface, charge is directly proportional to radius of curvature here `r_(D) gt r_(C) gt r_(B) gt r_(A)` and surface charge density is inversly proportional to radius of curvature. `sigma_(A) gt sigma_(B) gt sigma_(C) gt sigma_(D)` Electricfied is directly proportional to surface charge density `E_(A) gt E_(B) gt E_(C) gt E_(D)`

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In the following figure an isolated charged conductor is shown. The correct statement will be - A. `E_(A) gt E_(B) gt E_(C) gt E_(D)`B. `E_(A) lt E_(B) lt E_(C) lt E_(D)`C. `E_(A)=E_(B)=E_(C)=E_(D)`D. `E_(B)=E_(C)` and `E_(A) gt E_(D)`

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