1.

In the following figure. \(\frac{QR}{QS} = \frac{QT}{PR}\)  and ∠1 = ∠2. Show that ∆PQS ~ ∆TQR.

Answer»

Data: Here \(\frac{QR}{QS} = \frac{QT}{PR}\)  and ∠1 = ∠2

To prove: ∆PQS ~ ∆TQR. 

In ∆PQS and ∆TQR, we have

\(\frac{QR}{QS} = \frac{QT}{PR}\)

∠PQR = ∠PRQ (∵ ∠1 = ∠2) 

Here, Similarity criterion used here is side, angle, side (SAS). 

∴ ∆PQS ~ ∆TQR.



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