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In the following figure. \(\frac{QR}{QS} = \frac{QT}{PR}\) and ∠1 = ∠2. Show that ∆PQS ~ ∆TQR. |
Answer» Data: Here \(\frac{QR}{QS} = \frac{QT}{PR}\) and ∠1 = ∠2 To prove: ∆PQS ~ ∆TQR. In ∆PQS and ∆TQR, we have \(\frac{QR}{QS} = \frac{QT}{PR}\) ∠PQR = ∠PRQ (∵ ∠1 = ∠2) Here, Similarity criterion used here is side, angle, side (SAS). ∴ ∆PQS ~ ∆TQR. |
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