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| 1. |
In the following figure, if `PQ = R` (P is the centre of the bigger circle) and the shaded area is equal to A, then the radius of the inner circle is equal to - A. `(pi R-A)`B. `sqrt((piR-(A)/(pi)))`C. `sqrt(R-(A)/(pi))`D. `sqrt(R^(2)-(A)/(pi))` |
| Answer» Correct Answer - D | |