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In the following figure. ∆OBA ~ ∆ODC, ∠BOC = 125° and ∠CDO = 70°. Find ∠DOC, ∠DCO and ∠OAB. |
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Answer» ∆OBA ~ ∆ODC (data) In ∆OBA and ∆ODC, we have ∠ODC = ∠OBA = 70° (. Alternate angle) ∠AOB = 180°- 125° = 55° ( Adjacent angle) ∴ ∠AOB = ∠DOC = 55° (: VertIcally opposite angles) ∠OAB = ∠OCD = 55° (. Alternate angles) ∴ ∠DOC=55° ∠DCO = 55% ∠OAB= 55%. |
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