1.

In the following figure. ∆OBA ~ ∆ODC, ∠BOC = 125° and ∠CDO = 70°. Find ∠DOC, ∠DCO and ∠OAB.

Answer»

∆OBA ~ ∆ODC (data) 

In ∆OBA and ∆ODC, we have 

∠ODC = ∠OBA = 70° (. Alternate angle) 

∠AOB = 180°- 125° = 55° ( Adjacent angle) 

∴ ∠AOB = ∠DOC = 55° (: VertIcally opposite angles) 

∠OAB = ∠OCD = 55° (. Alternate angles) 

∴ ∠DOC=55° 

∠DCO = 55% 

∠OAB= 55%.



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