1.

In the following figure, what is the value of I?(a) I = IV + Ir(b) I = IV – Ir(c) I = IV Ir(d) I = ^IV ⁄ IrI had been asked this question in a national level competition.This interesting question is from Measurement of Low Resistance in portion Measurement of Resistance of Electrical Measurements

Answer»

The CORRECT choice is (a) I = IV + Ir

To explain: By applying Kirchhoff’s current law at the node N from FIG we get,

I = IV + Ir

where,

I is the total series current flowing through the circuit

Iv is the current flowing through the voltmeter

Ir is the current flowing through the resistance R.



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