InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
In the following potentiometer circuit AB is a uniform wire of length 1 in and resistance R the potential gradient along the wire and balance length AO (= l). |
|
Answer» SOLUTION :Current flowing in the potentiometer wire `I=E/(R_"total ")=20/(15+10)=2/25A` `:.` Potential DIFFERENCE across the wire `=2/25xx10=20/25=0.8A` `:.` Potential gradient `k=(V_(AB))/(I_(AB))=0.8/1.0=0.8V//m` Now, current flowing in the circuit containing experimental cell, `=15/(1.2+0.3)=1A` Potential difference across LENGTH `AO – 0.3 xx 1 = 0.3 V` Length`AO=(0.3)/(0.8)m=0.3/0xx100cm = 37.5cm ` |
|