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| 1. |
In the following potentiometer circuit AB is a uniform wire of length 1 in and resistance R the potential gradient along the wire and balance length AO (= l). |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Current flowing in the potentiometer wire <br/> `I=E/(R_"total ")=20/(<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a>+10)=2/25A` <br/> `:.` Potential <a href="https://interviewquestions.tuteehub.com/tag/difference-951394" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFERENCE">DIFFERENCE</a> across the wire `=2/25xx10=20/25=0.8A`<br/> `:.` Potential gradient `k=(V_(AB))/(I_(AB))=0.8/1.0=0.8V//m` <br/> Now, current flowing in the circuit containing experimental cell, <br/> `=15/(1.2+0.3)=1A` <br/> Potential difference across <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> `AO – 0.3 xx 1 = 0.3 V` <br/> Length`AO=(0.3)/(0.8)m=0.3/0xx100cm = 37.5cm `</body></html> | |