InterviewSolution
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InterviewSolution
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In the following process of disproportionation `2CIO_(3)^(-)hArrCiO_(2)^(-)+CIO_(4)^(-)` `E_(CIO_(4)^(-)//CIO_(3)^(-))^(@)=+0.36V,E_(CIO_(3)^(-)//CIO_(2)^(-))^(@)=+0.33V` If initial concentration of chloride ion was 0.1M, calculate the equilibrium concentration of perchlorate ion. |
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Answer» The two reactions of the given reaction will be `CIO_(3)^(-)(aq)+H_(2)O(l)toCIO_(4)^(-)(aq)+2H^(+)(aq)+2e^(-)` `underline(" "CI_(3)^(-)(aq)+2H^(+)(aq)+2e^(-)toCIO_(2)^(-)(aq)+H_(2)O(l)" ")` Adding `2CIO_(3)^(-)(aq)hArrCIO_(2)^(-)(aq)+CIO_(4)(aq)` `E_(cell)^(@)=0.33-0.36=-0.03V` `E=E^(@)-(0.059)/(n)logQ` At equilibrium, `E=0,Q=K_(eq)`. also n=2, hence `0=-0.03-(0.059)/(2)logK_(eq)` or `logK_(eq)=-(0.03xx2)/(0.059)=-1=overline(1)` or `K_(eq)=0.1` `{:(,2CIO_(3)^(-)(aq),hArr,CIO_(3)^(-)(aq),+,CIO_(4)^(-)(aq)),("Initial conc.",0.1M,,0,,0),("At eqm.",0.1-2x,,x,,x):}` `K=(x xx x)/((0.1-2x)^(2))=0.1` or `(x)/(0.1-2x)=sqrt(0.1)=0.316` or `x=0.0316-0.632` or `1.632x=0.0316` or `x=0.0194M` |
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