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In the following reaction overset(ɵ)(O)H+S_(2)O_(3)^(2-)+Br_(2)toSO_(4)^(2-)+Br^(ɵ) Starting with 0.15 " mol of "Br^(2) 0.01 " mol of "S_(2)O_(3)^(2-) and 0.4 " mol of "overset(ɵ)(O)H ions. How many moles of overset(ɵ)(O)H ions are left in the solution after the reaction is complete. |
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Answer» Solution :BALANCE the equation in basic medium `10H+S_(2)O_(3)^(2-)to2SO_(4)^(2-)+5H_(2)O+8e^(-)` `underline(2e^(-)+Br_(2)to2Br^(ɵ)]xx4)` `underline(4Br_(2)+S_(2)O_(3)^(2-)+10overset(ɵ)(O)Hto2SO_(4)^(2-)+8Br^(ɵ)+5H_(2)O)` `{:[(mol es),(befo re),(REACTION)](0.15)(0.01)(0.4)(0)(0)(0)` `{:[(mol es),(REACTED),(and),(fo rmed)]:}(0.01xx4)(0.01)(0.01xx10)(0.01xx2)(0.01xx8)(0.01xx5)` `{:[(mol es),(l eft)]:}[0.15-0.04]0(0.4-0.1)(0.02)(0.08)(0.05)(=0.11)(=0.3)` So, molar ratio of combination is: `Br_(2):S_(2)O_(3)^(2-):overset(ɵ)(O)H::4:1:10` `[overset(ɵ)(O)H]` LEFT after reaction `=0.3` mol |
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