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In the following reaction sequence, products I, J, and L are formed. `K` represents a reagent. The structures of product `I` is : The structures of compounds `J` and `K`, respectively, are : The structure of product `L` is : A. B. C. D. |
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Answer» Correct Answer - D `NaBH_(4)` reduces CHO selectively into `CH_(2)OH`, which is further converted into corresponding bromide by `PBr_(3)` without affecting the triple bond. |
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