In the following reaction sequence, the amount of D (in g) formed formed from 10 moles of acetic acid is ….. (The yield (%) corresponding to the product in each step is given in the parenthesis) CH_3COOH overset"NaOH"to underset"90%""A"underset"630 K"overset"Soda-lime"tounderset"70%""B"overset(Cl_2,hv)tounderset"80%""C"overset"Na,dry ether"tounderset"70%""D"

In the following reaction sequence, the amount of D (in g) formed form

1.	In the following reaction sequence, the amount of D (in g) formed formed from 10 moles of acetic acid is ….. (The yield (%) corresponding to the product in each step is given in the parenthesis) CH_3COOH overset"NaOH"to underset"90%""A"underset"630 K"overset"Soda-lime"tounderset"70%""B"overset(Cl_2,hv)tounderset"80%""C"overset"Na,dry ether"tounderset"70%""D"
Answer» Solution :The complete sequence of REACTION is : `underset"(2 MOLES)"underset"Acetic acid"(CH_3COOH) underset(-H_2O)overset"NaOH"to underset("Sod. acetate (A) 90%")(CH_3COONA) underset"630 K"overset"Soda-lime"to underset"Methane (B) (70%)"(CH_4)underset"Chlorination"overset(Cl_2, hv)to underset"Methyl chloride (C )80%" (CH_3-Cl) underset"Wurtz reaction"overset"Na, dry ether"to underset"(1 mole)"underset"ETHANE (D)"(CH_3-CH_3)` From the equations it is evident that 2 moles of acetic acid YIELD ethane = 1 mole `therefore` 10 moles of acetic acid will yield ethane =`10/2` moles Yield of D (in moles ) =`10/2xx90/100xx70/100xx80/100xx70/100=1.764` Mol. mass of ethane =30 `therefore` Yield of D (in g )= 1.764 x 30 = 52.92