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In the following reaction sequence, the products `(B)` to `( E)` are formed. . The structure of product `(B)` is :A. B. C. D. |
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Answer» Correct Answer - C ( c) `LiAlH_4` reduces `(C -= C)` to `(C = C)` bond in anti manner to give trans-alkene and also reduces `(CHO)` group to `(-CH_2OH)` group. Hence, the answer is `( c)`. |
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