In the Following reaction using isotope ""^(18)O in H_(2)O_(2). 2MnO_(4)^(-) + 3H_(2)O_(2)^(18) to 2MnO_(2) + 3O_(2) + 2H_(2)O + 2OH^(-) Isotopic oxygen goes :

In the Following reaction using isotope ""^(18)O in H_(2)O_(2). 2MnO_(

1.	In the Following reaction using isotope ""^(18)O in H_(2)O_(2). 2MnO_(4)^(-) + 3H_(2)O_(2)^(18) to 2MnO_(2) + 3O_(2) + 2H_(2)O + 2OH^(-) Isotopic oxygen goes :
Answer» both in `O_(2)` both in `MnO_(2)` both in `OH^(-)` One in `O_(2)` and one in `MnO_(2)` Solution :`H_(2)""^(18)O_(2) (aq) + 2OH^(-) (aq) to 2H_(2)O (l) + ""^(18)O_(2) (G) + 2e^(-)` So, all the `""^(18)O` LABEL appers in `""_(18)O_(2)`