In the following reactions, Aoverset("HBr,dark")underset("in the absence of peroxide")rarrunderset(("Major product"))(A)+underset(("Minor products" ))(B) the major prducts (A) and (C) are respecitvely.

In the following reactions, Aoverset("HBr,dark")underset("in the abs

1.	In the following reactions, Aoverset("HBr,dark")underset("in the absence of peroxide")rarrunderset(("Major product"))(A)+underset(("Minor products" ))(B) the major prducts (A) and (C) are respecitvely.
Answer» Solution : In this case dehydration is governed by Saytzeff's rule according to which hydrogen is preferentially eliminated from the carbon atom with fewer number of hydrogen atoms, `i.e.,` POOR BECOMES POORER. Thus, `2-`methyl butane `-2` is the major product. This reaction is governed by Maarkovnikov's rule according to which when an unsymmetrical reagent, `e.g., HBr` adds to an unsymmetrical alkene, then the negative part of the reagent is ADDED to that carbon atom of the double BOND which bears the least number of hydrogen atom. Thus, in the above case `2-` methyl `2-` bromo butane will be the major product.