In the following sequence of reactions, the amountof D (in g) formed from 72 g of Mg is……….. (The yield (%) corresponding to the product in each step is given in the parenthesis) underset(72g)Mgunderset("Strong heating")overset(N_(2),"excess")tounderset(100%)Aoverset(H_(2)O)tounderset((90%))Boverset("conc."HNO_(3))tounderset((80%))Coverset("Heat")tounderset((90%))D

In the following sequence of reactions, the amountof D (in g) formed f

1.	In the following sequence of reactions, the amountof D (in g) formed from 72 g of Mg is……….. (The yield (%) corresponding to the product in each step is given in the parenthesis) underset(72g)Mgunderset("Strong heating")overset(N_(2),"excess")tounderset(100%)Aoverset(H_(2)O)tounderset((90%))Boverset("conc."HNO_(3))tounderset((80%))Coverset("Heat")tounderset((90%))D
Answer» Solution :The complete sequence of reactions is : `underset(("3moles"))underset(72g)(Mg)underset("STRONG heating")overset(N_(2),"excess")tounderset(A(100%))(Mg_(3)N_(2))underset(-3Mg(OH)_(2))overset(H_(2)O)to` `underset(B(90%))(2NH_(3))overset("Conc".HNO_(3))tounderset(C(80%))(2NH_(4)NO_(3))overset(Delta)tounderset(+2H_(2)O)underset("2 moles")underset(2xx44g)(2N_(2)O)` `:'` Mol.mass of `N_(2)O=44` amu Now, 72 g of Mg give `N_(2)O=2xx44g` Amount of D (in g) `=2xx44xx(100)/(100)xx(90)/(100)xx(80)/(100)xx(90)/(100)` `=57.024g` `=57.02 g`