In the formula P(E) = \(\frac{n(E)}{n(S)}\) ; n(E) represents A) N

1.	In the formula P(E) = \(\frac{n(E)}{n(S)}\) ; n(E) represents A) No. of favourable outcomes B) No. of not favourable outcomes C) Total no. of outcomes D) Probability of event
Answer» Correct option is (A) No. of favourable outcomes \(\because\) P(E) \(=\frac{n(E)}{n(S)};\) where n(E) represents no. of favourable outcomes & n(S) represents total possible outcomes. Hence, option (A) is correct. A) No. of favourable outcomes

In the formula P(E) = \(\frac{n(E)}{n(S)}\) ; n(E) represents A) No. of favourable outcomes B) No. of not favourable outcomes C) Total no. of outcomes D) Probability of event

Answer»

Correct option is (A) No. of favourable outcomes

\(\because\) P(E) \(=\frac{n(E)}{n(S)};\) where n(E) represents no. of favourable outcomes & n(S) represents total possible outcomes.

Hence, option (A) is correct.

A) No. of favourable outcomes

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In the formula P(E) = \(\frac{n(E)}{n(S)}\) ; n(E) represents A) No. of favourable outcomes B) No. of not favourable outcomes C) Total no. of outcomes D) Probability of event

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