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In the formula `S=(n)/(2)[2a+(n-1)d]`, make a as the subject of the formula. |
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Answer» Given `S=(n)/(2)[2a+(n-1)d]` `implies(2S)/(n)=2a+(n-1)d` `implies2a=(2S)/(n)-(n-1)d` `impliesa=(S)/(n)-(n-1)(d)/(2)` |
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