In the formula, X = 3 YZ^(2),X has dimensions of capacitance and Z has dimensions of magnetic induction. The dimensions of Y are

In the formula, X = 3 YZ^(2),X has dimensions of capacitance and Z has

1.	In the formula, X = 3 YZ^(2),X has dimensions of capacitance and Z has dimensions of magnetic induction. The dimensions of Y are
Answer» `[M^(-3)L^(-2)T^(-2)A^(4)]` `[ML^(-2)T^(2)A^(2)]` `[M^(-3)L^(-2)A^(4)T^(4)]` `[M^(-3)L^(-2)T^(8)A^(4)]` SOLUTION :As q= CV `:. C= (Q)/(V)= (q^(2))/(W)` [as `V= (W)/(q)`] `:. [X]= [C]= [(A^(2)T^(2))/(ML^(2)T^(-2))]= [M^(-1)L^(-2)T^(4)A^(2)]` As `F= BIIsintheta :. B= (F)/(II sintheta)` `:. [Z]= [B]= [(MLT^(-2))/(AL)]= [ML^(0)T^(-2)A^(-1)]` GIVEN : `X= 3YZ^(2)` or `Y= (X)/(3Z^(2))` `:. [Y]= ([X])/([Z]^(2))= ([M^(-1)L^(-2)T^(4)A^(2)])/([ML^(0)T^(-2)A^(-1)]^(2))= [M^(-3)L^(-2)T^(8)A^(4)]`