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In the formula `X = 3YZ^(2),X and Z` have dimensions of capacitance and magnetic induction respectively. The dimensions of `Y` in MKSQ system are ………………, …………………. |
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Answer» Correct Answer - `[M^(-3)L^(-2)T^(4)Q^(4)]` `[X]=["capacitance"]=[M^(-1)L^(-2)Q^(2)]` and `[Z]=["Magnetic induction"]=[MT^(-1)Q^(-1)]` Therefore `[Y]=([X])/([Z]^(2))=([M^(-1)L^(-2)T^(2)Q^(2)])/([MT^(-1)Q^(-1)]^(2))=[M^(-3)L^(-2)T^(4)Q^(4)]` |
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