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In the frame work of wires shown in figure, a current I ampere is flowing. Find the magnetic field at O. |
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Answer» Let `hatn` be the unit vector perpendicular to the plane of frame work upwards. Total magnetic field at P is `vecB_0=vecB_1+vecB_2+vecB_3+vecB_4` `=(mu_0)/(4pi)I/r_1(2pi-alpha)(-hatn)+0+(mu_0)/(4pi)I/r_2alpha(-hatn)+0` `=(mu_0)/(4pi)I((2pi-alpha)/(r_1)+alpha/r_2)(-hatn)` `B_0=(mu_0)/(4pi)I((2pi-alpha)/(r_1)+alpha/r_2)` The direction of `vec(B_(0))` is perpendicular to the plane of framework of wire directed inwards. |
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