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In the given arrangement of capacitors, `6muC` charge is added to point a. Find the charge on upper capacitor. A. `3muC`B. `1muC`C. `2muC`D. `6muC` |
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Answer» Correct Answer - A a. `(q_(1))/(1)=(q_(2))/(2)=(q_(3))/(3)=K` `q_(1)+q_(2)_q_(3)=6` Solving. We get `K=1` or `q_(1)-3muC` |
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