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In the given circuit as shown below calculate the magnitude and direction of the current |
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Answer» Effective resistance of the circuit is `R_(eff)=2+2+1=5Omega` `therefore` total current in the circuit is `i=(V_(1)-V_(2))/(R_(eff))` `i=(10-15)/(5)=1A` Since the cell of larger emf decides the direction of low of current the direction of current in the circuit is from A to B through e |
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